2/(x^2-4)-1/(x^2-2x)+(x-4)/(x^2+2x)=0

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Solution for 2/(x^2-4)-1/(x^2-2x)+(x-4)/(x^2+2x)=0 equation: 



2/(x^2-4)-1/(x^2-2x)+(x-4)/(x^2+2x)=0



Domain of the equation: (x^2-4)!=0

We move all terms containing x to the left, all other terms to the right

x^2!=4

x^2!=4/

x^2!=√1/0

x!=1

x∈R





Domain of the equation: (x^2-2x)!=0

x∈R





Domain of the equation: (x^2+2x)!=0

x∈R



We calculate fractions


(2*(x^2-2x)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x))+(-1*(x^2-4)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x))+((x-4)*(x^2-4)*(x^2-2x))/((x^2-4)*(x^2-2x)*(x^2+2x))=0



We calculate terms in parentheses: +(2*(x^2-2x)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x)), so:

2*(x^2-2x)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x)

We multiply all the terms by the denominator


2*(x^2-2x)*(x^2+2x))

Back to the equation:

+(2*(x^2-2x)*(x^2+2x)))





We calculate terms in parentheses: +(-1*(x^2-4)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x)), so:

-1*(x^2-4)*(x^2+2x))/((x^2-4)*(x^2-2x)*(x^2+2x)

We multiply all the terms by the denominator


-1*(x^2-4)*(x^2+2x))

Back to the equation:

+(-1*(x^2-4)*(x^2+2x)))





We calculate terms in parentheses: +((x-4)*(x^2-4)*(x^2-2x))/((x^2-4)*(x^2-2x)*(x^2+2x)), so:

(x-4)*(x^2-4)*(x^2-2x))/((x^2-4)*(x^2-2x)*(x^2+2x)

We multiply all the terms by the denominator


(x-4)*(x^2-4)*(x^2-2x))

Back to the equation:

+((x-4)*(x^2-4)*(x^2-2x)))

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